Subscribe to:
Post Comments (Atom)
skip to main |
skip to sidebar
visitor map
Blog Archive
-
▼
2008
(41)
-
▼
November
(12)
- second derivative test
- optimization.Day1
- Nov. 21 Related Rates and homework hint
- related rates similar figures
- Related rates Day 2 - changing angles
- Student notes November 14 -November 25
- Related Rates Day 1
- Implicit differentiation - Find vertical and horiz...
- chain rule day 3
- chain rule day 2
- Chain Rule Day 1
- Answers to test review
-
▼
November
(12)
3 comments:
Notes for Friday, November 14th.
We began class by reviewing the previous nights homework about the height of a ladder as it's base moved further and further away from the wall. We discovered that the change in height was not constant. We then discussed a method used to find the change in height in regards to the change in distance of the base from the wall. This method is called "Related Rates". The first, and one of the most important, step is to write out what information you are given and then write down what information you are trying to find. Then you solve for one variable in terms of another. After you have done that, you find the derivatives of both variables using the information you were given and the other information you solved for. After learning this method, we practiced it with several different types of questions. Mr. Hansen has put up the smartboard notes and examples elsewhere on the blog.
-Charley Field
Notes for Tuesday Nov 18th.
After walking into class we received a three dimensional related rates problem. It was concerned with the rate at which water fills a "triangular prism." For further information on this problem please consult the Picsa uploaded notes. After solving this problem we, did a practice problem, which concerned fluids filling up cone shaped tanks.The key to the three dimensional problems is that when implicit differentiation is applied there are two unknowns. To solve these kinds of problems one must find a way to relate these variables. This can be done through the utilization of similar triangles or proportional ratios. Since we are often filling up basins with fluids, the shape of the fluid will assume that of its container and thus have proportional ratios.
-ALEX MARKOV
Notes for Monday November 17:
Today in class we continued to look at related rates problems. We worked on a hand out that included finding the derivatives for the rates of change of angles. With these problems we also used the trigonometric functions when solving.
Post a Comment